Question

8X^4+4X²=2X(X³+X)

Answer 1

remove the brackets
2x(x^3 + x) = 2x^4 + 2x^2

Now setting the two equal to each other
8x^4 + 4x^2 = 2x^4 + 2x^2
6x^4 + 2x^2 = 0
2x^2(3x^2 + 1) = 0

Now you can you that other theorem of -b +- the square root of b^2 times - 4 yada yada or you can set 2x^2 = 0 and 3x^2 + 1 = 0 (which I think is better here).

Answer 2

Oh and the two x values will be the roots of the equation (the points where the graph cuts the x-axis).

Answer 3

Everything good and understood?