Mathematics
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OpenStudy (anonymous):
which of the following is a factor or the trinomial below x^2 + x -12 A.(x-3) B. (x+3) C.(x+6) D.(x-4)
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OpenStudy (xapproachesinfinity):
What are the two numbers if you multiply them you get 12 and if you add them you get 1. Think about factors of 12
OpenStudy (anonymous):
alight where do i go from there ?
OpenStudy (xapproachesinfinity):
Do you know the two numbers or not
OpenStudy (anonymous):
two numbers that you get to 12 ?
OpenStudy (xapproachesinfinity):
Yes if you multiply them you get 12
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OpenStudy (anonymous):
2 and 6 ?
OpenStudy (xapproachesinfinity):
True but those two if you add them you don't get 1. What else
OpenStudy (anonymous):
okay you have to add it and get one thats what i wasnt getting
OpenStudy (xapproachesinfinity):
Give me a moment I will open my laptop ok
OpenStudy (anonymous):
ok
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OpenStudy (xapproachesinfinity):
Alright! know I can Explain to you nicely
OpenStudy (xapproachesinfinity):
(x+a)(x+b)=x^2+(a+b)x+ab. we're doing this factorization
OpenStudy (xapproachesinfinity):
a.b= -12, a+b= 1 do you agree
OpenStudy (anonymous):
yes
OpenStudy (xapproachesinfinity):
Good! now what we need to do is to find two number that will give us that -12 and if we add them they give us 1. you sad 2 and 6. let's check
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OpenStudy (anonymous):
thats not going to work ik already
OpenStudy (xapproachesinfinity):
2x6=12, 2+6= 8, let's check negative case -2x6=-12 , -2 +6=4
OpenStudy (xapproachesinfinity):
yeah i know I'm just going to show you how it works
OpenStudy (xapproachesinfinity):
now let's think about another two numbers that multiply to 12
OpenStudy (xapproachesinfinity):
can you tell me?
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OpenStudy (anonymous):
cant think of any that would add to one
OpenStudy (xapproachesinfinity):
just for the moment think about any two that multiply to 12 okay
do you know what are the factor of 12?
OpenStudy (xapproachesinfinity):
factor of 12 are the numbers that divide 12? you know this right
OpenStudy (anonymous):
yes
OpenStudy (xapproachesinfinity):
{1,2,3,4,6,12} Do you agree that this is the factors of 12?
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OpenStudy (anonymous):
yeah
OpenStudy (xapproachesinfinity):
we tried 2 and 6, can we try now 3 nd 4?
OpenStudy (xapproachesinfinity):
think about negative sign too not just 3 and 4
it could be -3,4 or -4,3. well actually you need a negative there since we need -12
OpenStudy (xapproachesinfinity):
do you agree
OpenStudy (anonymous):
yeah we need to use -3 ,4
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OpenStudy (xapproachesinfinity):
ok can you try that if it works?
OpenStudy (anonymous):
it does you get one i did it
OpenStudy (xapproachesinfinity):
take your time and do it neatly
OpenStudy (xapproachesinfinity):
Good job!
OpenStudy (xapproachesinfinity):
So now lets put it in this since a=-3 and b=4
we say that (x-3)(x+4)=x^2+x-12 do you agree
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OpenStudy (xapproachesinfinity):
that's what we found right?
OpenStudy (anonymous):
yep
OpenStudy (xapproachesinfinity):
So x^2+x-12 is factorized to (x-3)(x+4)
can we say the answer to the question is A: (x-3)
OpenStudy (xapproachesinfinity):
because if we multiply (x-3) with (x+4) we get the original trinomial
OpenStudy (anonymous):
ohh i get it more than i did thank you
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OpenStudy (xapproachesinfinity):
Great job, you did here! you see you can do this. practice more of this and you will master it. And pleasure to help you!
OpenStudy (xapproachesinfinity):
Just follow the same technique, it will always work for you
OpenStudy (anonymous):
will do
OpenStudy (xapproachesinfinity):
Okay good!