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OpenStudy (anonymous):
PLEASE HELP AND WILL GIVE A MEDAL! Please need help!!
Subtract and simplify 4a+1/a^2-4-3a+4/a^2-4
A. 8/a^2-4
B. a-3/a^2-4
C. 3/a+2
D. 2a-6/a^2-4
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OpenStudy (solomonzelman):
I am guessing the question is, \(\normalsize\color{blue}{ \frac{ \LARGE{4a+1} }{\LARGE{a^2-4}} -\frac{ \LARGE{3a+4} }{\LARGE{a^2-4}} }\) right ?
OpenStudy (anonymous):
I thin so I can't really read what you put there my iPad is acting weird
OpenStudy (anonymous):
Oh it's showing up now. Yes it is
OpenStudy (solomonzelman):
4a+1 3a+4
──── ─ ───
a²-4 a² - 4
OpenStudy (solomonzelman):
You have the same denominators, so you can add them.
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OpenStudy (solomonzelman):
I mean subtract them.
jagr2713 (jagr2713):
is there an answer choice
jagr2713 (jagr2713):
its a pretty long explanation
OpenStudy (anonymous):
subtract in the numerator, leave the denominator alone
OpenStudy (anonymous):
\[4a+1-(3a+4)=4a+1-3a-4=a-3\]
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OpenStudy (anonymous):
the denominator stays the same, you get
\[\frac{a-3}{a^2-4}\]
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