Question

HELP PLS!

Answer 1

@precal @Melodysim

Answer 2

@study100

Answer 3

@aum

Answer 4

Find out one of the factors first.
If you look at the answer choices, (x-1) is a factor in the first two choices and (x+1) is a factor in the last two choices. That means either x =1 or x = -1 will make f(x) zero.
f(x) = x^3 + 8x^2 + 19x + 12
No point trying any positive x because each term in f(x) is positive and they will not add to zero. Therefore, all roots must be negative. This rules out the first two choices.
Try x = -2 in f(x)
f(-2) = (-2)^3 + 8(-2)^2 + 19(-2) + 12 = -8 + 32 - 38 + 12 = -2.
Therefore, (x+2) is NOT a factor which rules out C. So the only choice left is D.
But to make sure try, x = -1, x = -3, x = -4 and make sure f(x) goes to zero for each of those x values.