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Mathematics 7 Online
OpenStudy (anonymous):

HELP PLS!

OpenStudy (anonymous):

OpenStudy (anonymous):

@precal @Melodysim

OpenStudy (anonymous):

@study100

OpenStudy (anonymous):

@aum

OpenStudy (aum):

Find out one of the factors first. If you look at the answer choices, (x-1) is a factor in the first two choices and (x+1) is a factor in the last two choices. That means either x =1 or x = -1 will make f(x) zero. f(x) = x^3 + 8x^2 + 19x + 12 No point trying any positive x because each term in f(x) is positive and they will not add to zero. Therefore, all roots must be negative. This rules out the first two choices. Try x = -2 in f(x) f(-2) = (-2)^3 + 8(-2)^2 + 19(-2) + 12 = -8 + 32 - 38 + 12 = -2. Therefore, (x+2) is NOT a factor which rules out C. So the only choice left is D. But to make sure try, x = -1, x = -3, x = -4 and make sure f(x) goes to zero for each of those x values.

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