find (x+4) exponent of 2
x^2+8x+16
\[(x+4)^{2}\]
\[(x+4)^2=(x+4)(x+4)\] is a start then do the usual four multiplications
how? can you explain step by step? please
you can either use the FOIL method or you can multiply everything in the first parenthesis by everything in the second parenthesis.....so how do you want to proceed
but how does the foil method apply to that?
first of all, do you see how we got (x + 4)(x + 4) from (x + 4)^2 ?
oh okay i see now i was just going to ask. and then foil that, right?
right...do you know how ?
let me try it on paper
sure thing..
\[x{2} +8+4x\]
here the formula is a^2+2ab+b^2 here a=x, b=4
no... (x + 4)(x + 4) F -- multiply first terms in each set....x * x = x^2 O -- multiply outside terms in each set....x * 4 = 4x I -- multiply inside terms in each set...4 * x = 4x L -- multiply last terms in each set...4 * 4 = 16 so now we have.. x^2 + 4x + 4x + 16 -- combine like terms x^2 + 8x + 16 any questions ?
\[x{2} + 16+4x + 16 ???\]
ahhh i see what i did wrong.
nope no questions... for now. thanks for your help
anytime :)
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