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OpenStudy (imtiaz7):
x^2+8x+16
OpenStudy (nicoleced):
\[(x+4)^{2}\]
OpenStudy (anonymous):
\[(x+4)^2=(x+4)(x+4)\] is a start
then do the usual four multiplications
OpenStudy (nicoleced):
how? can you explain step by step? please
OpenStudy (texaschic101):
you can either use the FOIL method or you can multiply everything in the first parenthesis by everything in the second parenthesis.....so how do you want to proceed
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OpenStudy (nicoleced):
but how does the foil method apply to that?
OpenStudy (texaschic101):
first of all, do you see how we got (x + 4)(x + 4) from (x + 4)^2 ?
OpenStudy (nicoleced):
oh okay i see now i was just going to ask. and then foil that, right?
OpenStudy (texaschic101):
right...do you know how ?
OpenStudy (nicoleced):
let me try it on paper
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OpenStudy (texaschic101):
sure thing..
OpenStudy (nicoleced):
\[x{2} +8+4x\]
OpenStudy (imtiaz7):
here the formula is
a^2+2ab+b^2
here a=x, b=4
OpenStudy (texaschic101):
no...
(x + 4)(x + 4)
F -- multiply first terms in each set....x * x = x^2
O -- multiply outside terms in each set....x * 4 = 4x
I -- multiply inside terms in each set...4 * x = 4x
L -- multiply last terms in each set...4 * 4 = 16
so now we have..
x^2 + 4x + 4x + 16 -- combine like terms
x^2 + 8x + 16
any questions ?
OpenStudy (nicoleced):
\[x{2} + 16+4x + 16 ???\]
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OpenStudy (nicoleced):
ahhh i see what i did wrong.
OpenStudy (nicoleced):
nope no questions... for now. thanks for your help