What is the equation of the line that contains the points (3, –6) and (–3, 0)?
A.
y = x – 3
B.
y = –x – 3
C.
y = –x + 3
D.
y = x + 3
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OpenStudy (anonymous):
ill give medal
OpenStudy (anonymous):
first of all you have to find the slope
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
do you know how to find the slope?
OpenStudy (anonymous):
you use the equation : (y2-y2)/(x2-x1)
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OpenStudy (anonymous):
y2-y1*
OpenStudy (anonymous):
so its 3,3 right
OpenStudy (anonymous):
what is 3,3?
OpenStudy (anonymous):
idk
OpenStudy (anonymous):
you just substitute into the equation :
(3,-6) (-3,0)
y2 = 0
y1 = -6
x2 = -3
x1= 3
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OpenStudy (anonymous):
so basically what would you get? (keeping in mind that the equation is y2-y1/x2-x1
OpenStudy (anonymous):
y=x+3
OpenStudy (anonymous):
right
OpenStudy (anonymous):
nope, try it again
look : it would be 0--6/ -3-3 = 6/-6 = -1 so the slope would be -x
OpenStudy (anonymous):
and the three would be positive
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
so basically we have found that the slope is -x, but we dont know what the y-intercept is, so for now, our equation is y=-x+c where c is the unknown y-interecept,
so you substitute into this equation using one of the points such as (-3,0)
so 0 = - (-3) + c
so 0 = 3 +c
so c = -3