What is the equation of the line that contains the points (3, –6) and (–3, 0)? A. y = x – 3 B. y = –x – 3 C. y = –x + 3 D. y = x + 3
ill give medal
first of all you have to find the slope
ok
do you know how to find the slope?
you use the equation : (y2-y2)/(x2-x1)
y2-y1*
so its 3,3 right
what is 3,3?
idk
you just substitute into the equation : (3,-6) (-3,0) y2 = 0 y1 = -6 x2 = -3 x1= 3
so basically what would you get? (keeping in mind that the equation is y2-y1/x2-x1
y=x+3
right
nope, try it again look : it would be 0--6/ -3-3 = 6/-6 = -1 so the slope would be -x
and the three would be positive
right
so basically we have found that the slope is -x, but we dont know what the y-intercept is, so for now, our equation is y=-x+c where c is the unknown y-interecept, so you substitute into this equation using one of the points such as (-3,0) so 0 = - (-3) + c so 0 = 3 +c so c = -3
ahh i get it now thank you
you're welcome :)
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