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Given f(x) = the quantity of 4x plus 1, divided by 3, solve for f-1(3).
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\[f(x) =\dfrac{4x+1}{3}\] right? I guide and you work, deal??
yup! so the answer would be 13/3
f(1)=3, f(0)=2 and f(-1)=1 These can be proved by putting the respective values of x in f(x). Do you get my point?
Confirm: what do you mean by f-1(3)?? is it \(f^-(3)\)
|dw:1406740677051:dw|
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my bad?
ok ok
wut?
nah its cool
well I have 1 more question after this!
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ok, @emmii2239 now, 1/ switch the role of f(x) and x on the expression above, what do you have? I mean if you see x, then replace by f-(x) , if you see f(x) , then replace by x show me what you get??
I dont get what youre saying
|dw:1406740921229:dw|
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