heellpppppp GEOMETRYYY
awww i hate this but i will help lmfao
thank you taz <3
anytime
i think its three but i would check wit other people to thnx and yw
alrighty thanks
The final equation came out to be AB+ED=x+4 Cant figure out after that. Maybe it gives you a clue :)
@mrgenius i dont get it
GOT IT !!!! THE ANSWER IS 2
DO YOU NEED EXPLANATION ? or you ok with the answer itself?
Google intersecting secant theorem. \[BC^2 = (CD)(CE)\]
We know BC, CD, and CE. This converts the problem into a quadratic formula.
@queelius soooo is it 2 or 3
its definetely 2 dear
I just calculated it. My approach didn't produce a reasonable answer.
@queelius You need to assume that AB and ED are of same length, or else you wont be able to solve it.
it was 2
MrGenius, tricky question. And, yes, I wasn't making that assumption. Btw, I realized why my approach failed: I was using the wrong formula.
hehe told you, its really tricky ! I LOVED solving this. Sometimes when you feel like you are trapped, always use the "assuming" formula :)
thanks guys
MrGenius, well, I didn't assume AB=DE because, based on the figure, they aren't equal.
ED's perpendicular distance to F is less than AB's.
You must assume, and not see the lines as real calculated figure
When I assumed AB=ED, then AB=ED=13, which produces non-sensical answers. How did you solve it?
@mrgenius
Assume AB=ED=y First Equation, AC=AB+BC 12=x+1+y 11=x+y........................(1) Second Equation, EC=ED+DC 9=2x+y.........................(2) Adding (1) and (2) x=2
got it ? @queelius
x=-2, y=13
Let's plug in x = 2. 9=2(2)+y, 11=2+y => y=5, y=9, inconsistent. x=-2 is consistent.
Here's how you must solve it. Secant-secant theorem: BC * AC = DC * EC
omg !!!!!!!!!!!! i remember this formula, and yea i forgot about the 'minus'
I had to Google the formula; I knew there had to be something that expressed the relationship we were after. :)
yes, so was i. But couldnt go on google as I was looking for quick solution. Thanks for the info
Aye, well, anyway, the right answer was given, but for the wrong reasons. It's always interesting when that happens. :)
That has saved me on many exams, but in my school days.
but in my school days=back in my school days
yes, but i believe majority of people dont really care about the approach. they are least bother to learn, they just want a right answer. I better have a girls pic to attract more number of fans lol
Eh, I'm not really trying to acquire fans. I come here to help and to try to find interesting problems to work on.
But, yeah, a girls pic would help. I doubt my dog pic is winning me any favors.
I just noticed your image.
I much prefer yours to any girl pic.
Hard to read though. :)
I dont want more fans either, but I just noticed that a lade as profile pic would only do good. The dog looks male so no...lol. I enjoy solving problems and its like a mental workout for me. Well the picture isnt gonna stop what is destined, lets just pray and hope for good.
i meant Lady*
It's a thorny problem, the Israeli/palestine situation. I don't have any answers.
That's why I prefer more objective problems, like math. :) And the math problem was also tricky, but solvable. :) See ya around.
Agree. Yeah see you around on other questions haha
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