Question

What is the product of the two real solutions of the equation


2x = 3 - x2


A) 3
B) 2
C) -2
D) 6
E) -3

Answer 1

6 min left 0.0

Answer 2

2*-3=3-(-3)*2 so that would be E see what happens

Answer 3

uh @ganeshie8 is it E????

Answer 4

r u done after this?????

Answer 5

I need 1 more and done

Answer 6

post the next 1 quick

Answer 7

how many mins

Answer 8

We can generalize our result to quadratic equations of the form \(p(x) = 0\) where \(p(x) = ax^2+bx+c = a(x^2+\frac bax+\frac ca)\)
\(p(x) = a(x-x_1)(x-x_2) = a(x^2-x(x_1+x_2)+x_1x_2))\)
We see that \(x_1x_2 = \cfrac ca\) for any quadratic equation!

In our case we can write \(x^2+2x-3 = 0\), so \(a = 1,\;c = -3\) and we have \(x_1x_2 = \frac{-3}{1} = -3\), as already said.