A flowerpot falls from the ledge of an apartment building. A person in an apartment below, coincidentally in possesion of a high-speed, high-precision timing system, notices that it takes 0.16 s to fall past his 4.8 m tall window. How far above the top of the window is the ledge from which the pot fell? answer needs to be in meters

Question

anonymous · Answer

$$x= V*T+.5a *T ^{2} $$
Since it fell the original velocity would be zero
and your left with $$x=1/2*a*T ^{2}$$
a= acceleration and the acceleration due to gravity is 9.8
and t is how long it takes to fall down
so 
$$x=4.9*.16^{2}$$
x=.12544 m
so the ledge is 4.8+.125544 m tall

anonymous · Answer

It say's that that's incorrect. It also says this... In the absence of air resistance, the acceleration of the flowerpot is constant. You will need to use two constant-acceleration expressions for the distance from the ledge to both the top and bottom of the window, and solve the resulting two equations simultaneously.

anonymous · Answer

Try 0.751m as the answer if it works i'll explain it if not i'll just try again

anonymous · Answer

doesn't work

anonymous · Answer

if it helps you any they give me practice questions and tell me the answers to those. For example : A flowerpot falls from the ledge of an apartment building. A person in an apartment below, coincidentally in possesion of a high-speed, high-precision timing system, notices that it takes 0.21 s to fall past his 3.3 m tall window. How far above the top of the window is the ledge from which the pot fell? 
the answer is 11m

anonymous · Answer

okay i think i figured it out try 43.5 as your answer

anonymous · Answer

How'd you get that? (sorry if that sounds rude, it's just that every time I put in a wrong answer my score decreases)

anonymous · Answer

okay so the first two times i didn't read the question properly i thought it took that long to hit the ground
 but what i was supposed to do was 
$$V2=V1+aT$$
a=9.8
T=0.16
$$V2^{2}=V1^{2}+2a DeltaX$$
$$\sqrt{V1^{2}+2a DeltaX}=V1+aT$$
simplifies to 
$$V1=(2DeltaX+aT ^{2})/2T$$=29.2
$$V1=aT1$$
simplifies to 
$$T1=V1/a$$
$$X=1/2*a*T1^{2}$$=43.5
use the same steps with the numbers that they give in the example problem and you should get 11

anonymous · Answer

$$DeltaX=4.8$$

anonymous · Answer

that's so confusing but fortunately it's correct. Thank you soo much for your time.

anonymous · Answer

do you think you could help me with a different question?

anonymous · Answer

yeah sure ill try to read it properly this time

anonymous · Answer

You are riding in a boat whose speed relative to the water is 5.0 m/s. The boat points at an angle of 25.8° upstream on a river flowing at 14.8 m/s. Find the time it takes for the boat to reach the opposite shore if the river is 26.5 m wide.