how do i factor x^1/2-3x?

Question

solomonzelman · Answer

You mean  $\normalsize\color{blue}{   x^{1/2}-3x   }$  right ?

anonymous · Answer

yes

solomonzelman · Answer

I do not think that you can factor such an expression though...

solomonzelman · Answer

You can re-write it in terms of a root,  $\normalsize\color{blue}{   \sqrt{x}-3x   }$ , and see why not ?

anonymous · Answer

can i simplify it then?

solomonzelman · Answer

No, I really don't think that you can do anything with it that would make it look any simpler than what it is now.

solomonzelman · Answer

I'll post a bit of instructions, okay ?

anonymous · Answer

Ok

jdoe0001 · Answer

$\Large \bf {
x^{\frac{1}{2}}-3x\implies x^{\frac{1}{2}}-3x^1\implies x^{\frac{1}{2}}-3x^{\frac{2}{2}}
\ \quad \
x^{\frac{1}{2}}-3x^{\frac{1}{2}+\frac{1}{2}}\implies x^{\frac{1}{2}}-3x^{\frac{1}{2}}x^{\frac{1}{2}}
}$

see any common factors?

anonymous · Answer

yes

jdoe0001 · Answer

so just take that common factor... and is all you could really factor it about, I'd think

solomonzelman · Answer

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solomonzelman · Answer

I meantion myself instead,... but I see you figured out some things already.

solomonzelman · Answer

Excuse the long reply.

anonymous · Answer

Its ok thanks so much for the help @SolomonZelman

solomonzelman · Answer

Anytime !