Question

Find the first six terms of the sequence.

a1 = 4, an = an-1 + 8

Answer 1

The difference is 8, and the first term is 4.

\(\large\color{blue}{ a_n=a_1+d(n-1) }\)

\(\large\color{blue}{ a_6=4+8(6-1) }\)

So, \(\large\color{blue}{ a_6=? }\)

Answer 2

a6=44

Answer 3

\(\large \begin{array}{ccllll}
term&value
\\\hline\\
a_1&4\\
a_{\color{brown}{ 2}}&a_{{\color{brown}{ 2}}-1}+8\to a_1+8\\
a_{\color{brown}{ 3}}&a_{{\color{brown}{ 3}}-1}+8\to a_2+8\\
a_{\color{brown}{ 4}}&a_{{\color{brown}{ 4}}-1}+8\to a_3+8\\
a_{\color{brown}{ 5}}&a_{{\color{brown}{ 5}}-1}+8\to a_4+8\\
a_{\color{brown}{ 6}}&a_{{\color{brown}{ 6}}-1}+8\to a_5+8\\

\end{array}\)

Answer 4

You could have just used a chart latex.

Answer 5

do you think you guys could help me on other problems?

Answer 6

sure, just post anew...thus if we dunno, someone else may and we can revise each other

Answer 7

ok

Answer 8

I should post a chart ? Or what did you mean to post a few ?

Answer 9

NVM