which is the equation of a line that passes throughthe point (3, -4) and has a slope of 2
When we are given a point and a slope, we can find the equation of the line by using the following formula: \[(y- y_o )= m(x- x_o )\] where "m" is the slope we are given and "xo","yo" are the coordinates of the point we are also given.
I understand that but still can not figure what the answer to the problem would be. Do you know what the complete answer is?
Let's take the formula and set the data we have: \[(y+4)=2(x-3)\] Let's simplify it further: \[(y+4)=2x-6\] A equation of the line has several forms, but you only need to know two of them, wich are the point-slope form and the general form. The general form is when the whole equation is made equal zero: \[Ax+By+C=0\] And the point-slope form is pretty much isolating the "y" variable and the rest on the right side: \[y=mx+c\] Those are the two forms you can basically bring a line to. So let's retake the problem and say i want to bring it to it's point slope form, wich means I just want to isolate the y on the left side: \[(y+4)=2x-6\] \[y=2x -10\] And that is an answer. Why don't you try bringin it to it's general form?
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