Question

A solution is made by dissolving 1.00 moles of sodium chloride in 155 grams of water. If the molal boiling point constant water is .51 degrees C/m, what would be the boiling point of this solution?

Answer 1

\[DeltaTb=Kb*m\]
m=moles/kg of solvent
\[m=1/.155\]=6.452
\[DeltaTb=6.452*0.51=3.291\]
\[DeltaTb=Tbfinal-Tboriginal\]
\[Tbfinal=DeltaTb+Tboriginal=3.29+100\]
103.29 degrees Celsius is the new boiling point