Question

If A and B are independent events, P(A) = 0.4, and P(B) = 0.55, find the probabilities below.

P(A union B)_________

Answer 1

P(A or B)=P(A)+P(B)-P(A and B)
since there are independent event P(A and B)=0
So P(A or B)=P(A)+P(B)
just put in the number and you get the probab you are looking for

Answer 2

P(a and b) is the same as P(a union b), just for clarification

Answer 3

Does this make sense to you?

Answer 4

no, honestly

Answer 5

i got it. add the two numbers together then minus the intersection

Answer 6

P(A and B) = P(A)P(B) if they are independent
P(A and B) = 0 if A and B are mutually exclusive

Answer 7

Okay let's go slowly then lol
P(A union B) means the probability that A occurs or B occurs
there is a chance that A will occur or chance of b occurring
or may be the two event will both occur
what i'm saying now is translated to P(A union B)=P(A)+P(B)-P(A and B)

Answer 8

oh right! P(a and b) i got it wrong
case of independent it is as @kirbykirby

Answer 9

thanks for the correction^^

Answer 10

=]

Answer 11

I mixed those two, I haven't practiced this for some time

Answer 12

So our probabilty is P(A or B) = P(A)+P(B)-P(A)P(B)
since A and B are independent event P(A and B)= P(A)P(B)
like kirbykirby said above

Answer 13

Are you following, or perhaps I confused you lol