Question

PLEASE HELP, MEDAL AWARDED

Write an equation of a line that passes through the point (8, 4) and is parallel to the line y = 4x + 2.

y = 4x − 28

y = 4x + 28

y = x − 2

y = x + 2

Answer 1

they have the same slope since they are parallel... you can use point-slope form to find the equation...

Answer 2

first take out the slope from the given equation
that is
m1=4 and the line is parallel to this line
so slope will be equal
m1=m2
m2 =4
ookay now just point intercept form
and put this slope and given point in that
( y-y1) =m (x-x1)
(x1,y1)=(8,4)
m=4
now this is yur job

Answer 3

from slope-intercept form...\[y=mx+b\]\[y=4x+2\]the slope of the line is m=4

Answer 4

okay hold on

Answer 5

wait i can't go anywhere if y=4x+2 like where do i go now

Answer 6

A is the correct answer

Answer 7

thank you!

Answer 8

you can use point-slope form for the required line since it passes thru' the given point (8,4)...\[(y-y_1)=m(x-x_1)\]

Answer 9

y-4 =4(x-8)
y-4 = 4x -32
y=4x-32+4
y=4x -28
do u have any confussion /?
then ask me

Answer 10

most welcome