Question

please help me ill give u a medal
What is the standard form equation of the line shown below?

Answer 1

given points on the line (3,2) and (-3,-1)...

Answer 2

ya i think i know it would it be\[y+1=1/2x+3\]

Answer 3

slope is...\[m=\frac{-1-2}{-3-3}=\frac{-3}{-6}=\frac{1}{3}\]

Answer 4

ok what would i do now

Answer 5

i thought that that would be the answer up there

Answer 6

using point-slope form, it would be...\[(y-2)=\frac{1}{3}(x-3)\]\[3y-6=x-3\]\[3y=x-3+6=x+3\]\[y=\frac{1}{3}x+1\]

Answer 7

i need to find what the graph is in standard form

Answer 8

standard form of line is Ax + By + C=0

Answer 9

... it is x - 3y + 3 = 0

Answer 10

thats not an answer choice

Answer 11

the choices

Answer 12

@tkhunny can u help

Answer 13

... ok no problem... that's far i can go...

Answer 14

... btw... based on your graph... using the intercept form...\[\frac{x}{-1}+\frac{y}{\frac{1}{2}}=1\]\[-x+2y=1\]\[x-2y+1=0\]