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Mathematics 9 Online
OpenStudy (anonymous):

please help me ill give u a medal What is the standard form equation of the line shown below?

OpenStudy (anonymous):

OpenStudy (anonymous):

given points on the line (3,2) and (-3,-1)...

OpenStudy (anonymous):

ya i think i know it would it be\[y+1=1/2x+3\]

OpenStudy (anonymous):

slope is...\[m=\frac{-1-2}{-3-3}=\frac{-3}{-6}=\frac{1}{3}\]

OpenStudy (anonymous):

ok what would i do now

OpenStudy (anonymous):

i thought that that would be the answer up there

OpenStudy (anonymous):

using point-slope form, it would be...\[(y-2)=\frac{1}{3}(x-3)\]\[3y-6=x-3\]\[3y=x-3+6=x+3\]\[y=\frac{1}{3}x+1\]

OpenStudy (anonymous):

i need to find what the graph is in standard form

OpenStudy (anonymous):

standard form of line is Ax + By + C=0

OpenStudy (anonymous):

... it is x - 3y + 3 = 0

OpenStudy (anonymous):

thats not an answer choice

OpenStudy (anonymous):

the choices

OpenStudy (anonymous):

@tkhunny can u help

OpenStudy (anonymous):

... ok no problem... that's far i can go...

OpenStudy (anonymous):

... btw... based on your graph... using the intercept form...\[\frac{x}{-1}+\frac{y}{\frac{1}{2}}=1\]\[-x+2y=1\]\[x-2y+1=0\]

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