Question

∑5k = 1[8(k + 1)]

Answer 1

you mean
\(\Large \sum \limits_{k=1}^5 8(k+1)\)
?

Answer 2

yes

Answer 3

\(\sum \)
means summation.

so start plugging in k=1, then k=2...till k=5, and SUM all the results! :)

Answer 4

like for k=1, we get
\(8(1+1) = 8\times 2 =16\)

Answer 5

do it for k=2, k=3, k=4, k=5
then sum all the results

Answer 6

16+42+36+40+48???

Answer 7

42 and 36 are incorrect, how did you get them ?

Answer 8

8(2+1)=24
8(3+4)=32

just miscalculated

Answer 9

now all are correct :)
just sum them up!

Answer 10

160

Answer 11

\(\huge \checkmark \)

Answer 12

Thank you!!!

Answer 13

welcome ^_^

Answer 14

What about ∑20k = 1\[\Sigma^20 _1=_1k^2\] IDK how to get the 0 with the 2... @hartnn

Answer 15

you mean
\(\Large \sum \limits_{k=1}^{20} k^2 \)
?

Answer 16

but there is also a 1 before the k but it is _1 not just 1

Answer 17

'before' the k ??
then i am not sure what the question is asking...

Answer 18

so if i ignore the 1...

Answer 19

can you draw the question ?