Which statement is true about the product square root of 2(5 + square root of 8)?
@Purplerainbowcherry @RatzLover95 @Angel$18
@sloths
are there options?
Yes, here they are It is rational and equal to 7. It is rational and equal to 9. It is irrational and equal to 4 + square root of 10. It is irrational and equal to 4 + 5square root of 2. Dont know why they didnt post.. haha
I'm pretty sure its the last one
Why?
Need a little more info than, I think its the last one.. haha
Can you help with a few more problems after this one?
ok i'll try to explain best i can so you distribute the root 2 first which gives you\[\sqrt{10}+\sqrt{16}\] then you find the root of 16, which is 4 which then gives you \[4\sqrt{10}\] Then since 10 doesn't have a root you simplify it, giving you a final answer of \[4+5\sqrt{2}\]
I'm a bit busy but i could take a look
Gotcha. Sounds good.
Simplify. 4 square root of 2 end root plus 7 square root of 2 end root minus 3 square root of 2 2 square root of 8 8 square root of 2 8 square root of 6 6 square root of 8
Simplify. 4 square root of 2 end root plus 7 square root of 2 end root minus 3 square root of 2 2 square root of 8 8 square root of 2 8 square root of 6 6 square root of 8
Those two
they're the same question
hold on ill look at them
looks like this?\[4\sqrt{2}+7\sqrt{2}-3\sqrt{2}\]
Correct.
sure. that one you just add the outside numbers basically. so its 4+7-3 which equals 8 and then you put the root 2 on the end. your answer is \[8\sqrt{2}\]
Sweet! I put in the last problem I needed help with above. :) :p
I only see two questions, the ones i already answered
One second
Which statement is true about the difference square root of 7 - square root of 28? It is rational and equal to -2. It is rational and equal to 0. It is irrational and equal to -2square root of 7. It is irrational and equal tosquare root of 7
looks like this? \[\sqrt{7}-\sqrt{28}\]
No, |dw:1406840811533:dw|
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