Question

Help with Quadratic formula??

Answer 1

I don't think I did this right... use the quadratic formula on 2x^2 -12x + 5 = 0
I got this

x=(-b±√b^2-4ac)/2a

Now let's plug our equation in and simplify.

x=(-12±√144-4*2*5)/4

x=(-12±√144-4*10)

x=(-12±√144-40)

x=(-12±√104

Answer 2

Can someone show me how to do this correctly?

Answer 3

a = 2
b = -12
c = 5
\[X = \frac{ -(-12) \pm \sqrt{(-12)^2 - 4(2)(5)} }{ 2(2) } \]

Answer 4

\[X = \frac{ 12 \pm \sqrt{26 * 4} }{ 4 }\]\[X =\frac{ 12 \pm \sqrt{144 - 40} }{ 4 }\]
\[X = \frac{ 12 \pm \sqrt{104} }{ 4 }\]
\[x = \frac{ 12 \pm \sqrt {26*4} }{ 4 }\]
\[x = \frac{ 12 \pm 2\sqrt{26} }{ 4 }\]

Answer 5

then what?...

Answer 6

thats it..

Answer 7

thats the solution

Answer 8

\[x = \frac{ 6 \pm \sqrt{26} }{ 2 }\]well you could simplify it a bit more i guess

Answer 9

Hmmm okay