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OpenStudy (anonymous):

CAN SOMEONE PLEASE HELP?!?! Someone help for a medal? Using your function f(x) from question 2, demonstrate and explain how to find the average rate of change between year 3 and 5, and between year 5 and 7. Explain what the average rate of change represents to the frog population. y = 200(1.03^4. 200 this is the function I used

OpenStudy (mrnood):

Maybe you have written this function incorrectly. is it something like \[y=200\times (1.03)^{n} + 200\] Where n is th eyear number?

OpenStudy (anonymous):

Whoops, I just noticed my mistake. Thanks

OpenStudy (anonymous):

The question is asking: Create an exponential growth function, f(x), to model a population of frogs that is growing every year. Identify the principal amount, the growth rate, and the appropriate domain and range for your function. Explain how these key features would affect the graph of f(x). And this is my answer for the last question: The function would be: y=200×(1.03)n+200 which is the beginning number of frogs at 1.03, which means that the number of frogs is increasing by 3% a year and the 4 would be the number of years,4 years. So the y gives you the total number of frogs after 4 years, if you start with 200 frogs and they increase by 3% per year. Incase your confused with anything

OpenStudy (anonymous):

This is for the last question, which I do not need help with

OpenStudy (anonymous):

@MrNood ?

OpenStudy (anonymous):

Yes, it is

OpenStudy (mrnood):

So the function that oyu generated IS the same that I wrote? To find the average between two years calculate y for year 5, and for year 3 Subtract them - gives you the total growth, divide by 2 years for average per year Same for 7 and 5 As for what it means?

OpenStudy (anonymous):

So subtract 5 from 1.03?

OpenStudy (mrnood):

no you have an equation that tell you the population y for each year n put n = 5 and calculate y put n = 3 and calculate y subtract y5-y3 This gives you the total change in the population over 2 years. To get the AVERAGE over 2 years divide by 2

OpenStudy (anonymous):

Divide what by 2? 200 by 2?

OpenStudy (mrnood):

(y5-y3)/2

OpenStudy (anonymous):

I'm sorry, my brain is basically fried right now. I have been working for hours today and i can't think straight anymore.

OpenStudy (mrnood):

Ok - you'll have to come back to it when you can understand your own equation. I am not going to give you the answer

OpenStudy (anonymous):

I didn't tell you to give me the answer though :/

OpenStudy (mrnood):

No - but you said you cannot think - so you cannot do this question. Do oyu understand what the equation means?

OpenStudy (anonymous):

Yes, I do.

OpenStudy (mrnood):

so put n=5 and calculate y5 That is the population in year 5 Put n=3 and calculate y3 That is the population in year 3 So the total population change between yr 3 and yr 5 is y5-y3 (it IS a little confusing that you have used "y" for the population) The change is over 2 years so the average change is (y5-y3)/2

OpenStudy (anonymous):

Oohhhhhhh okay. I understand now. I'll be able to do the rest now. Thank you!

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