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Mathematics 15 Online
OpenStudy (dannyrod2000):

What is the simplified form of the rational expression.

OpenStudy (dannyrod2000):

6x^2-54/5x^2+15x

OpenStudy (agreene):

are you asking this? \[\frac{6x^3-54}{5x^2+15x}\]

OpenStudy (agreene):

6x^2 on that.

OpenStudy (dannyrod2000):

yes exactly

OpenStudy (dannyrod2000):

yea with 6x^2 instead of 6x^3

OpenStudy (agreene):

factoring would be a good start. Try factoring the numerator and denominator.

OpenStudy (dannyrod2000):

ok so for which number?

OpenStudy (agreene):

you can factor the top and the bottom, think of values you can pull out for each one

OpenStudy (dannyrod2000):

o i get it srry

OpenStudy (dannyrod2000):

(6x+9)(x-6)

OpenStudy (agreene):

the numerator would be done as such: \[6x^2-54 \rightarrow 6(x-3)(x+3)\]

OpenStudy (dannyrod2000):

can you please show me how

OpenStudy (dannyrod2000):

ohhhh

OpenStudy (dannyrod2000):

ok so 6*x would be 6x and x would be 6x^2 and 6*3 would be 18 and times 3 would be -54

OpenStudy (agreene):

\(6x^2-54\) pull 6 out for each \(6(x^2-9)\) divide parenthetical statement \(6(x-3)(x+3\)

OpenStudy (agreene):

right

OpenStudy (agreene):

now try the denominator

OpenStudy (dannyrod2000):

5(x+5)(x+3)?

OpenStudy (agreene):

taking out 5x would be more effective

OpenStudy (agreene):

since 15x is divisible

OpenStudy (dannyrod2000):

oh ok

OpenStudy (agreene):

\[5x^2+15x \rightarrow 5x(x-3)\]

OpenStudy (agreene):

so, then we would combine them: \[\frac{6(x-3)(x+3)}{5x(x-3)}\]

OpenStudy (dannyrod2000):

o so you cross out (x-3) and (x-3) and 6(x+3)/5x is the answer!

OpenStudy (agreene):

that can be the answer, technically you can simplify it a bit more. But that should be fine.

OpenStudy (dannyrod2000):

um i got it wrong :(

OpenStudy (dannyrod2000):

it was 6(x-3)/5x

OpenStudy (agreene):

yeah

OpenStudy (agreene):

i put the wrong sign on the 2nd factor. thats mah bad

OpenStudy (agreene):

5x^2+15 -> 5x(x+3)

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