Mathematics
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OpenStudy (dannyrod2000):
What is the simplified form of the rational expression.
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OpenStudy (dannyrod2000):
6x^2-54/5x^2+15x
OpenStudy (agreene):
are you asking this?
\[\frac{6x^3-54}{5x^2+15x}\]
OpenStudy (agreene):
6x^2 on that.
OpenStudy (dannyrod2000):
yes exactly
OpenStudy (dannyrod2000):
yea with 6x^2 instead of 6x^3
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OpenStudy (agreene):
factoring would be a good start. Try factoring the numerator and denominator.
OpenStudy (dannyrod2000):
ok so for which number?
OpenStudy (agreene):
you can factor the top and the bottom, think of values you can pull out for each one
OpenStudy (dannyrod2000):
o i get it srry
OpenStudy (dannyrod2000):
(6x+9)(x-6)
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OpenStudy (agreene):
the numerator would be done as such:
\[6x^2-54 \rightarrow 6(x-3)(x+3)\]
OpenStudy (dannyrod2000):
can you please show me how
OpenStudy (dannyrod2000):
ohhhh
OpenStudy (dannyrod2000):
ok so 6*x would be 6x and x would be 6x^2 and 6*3 would be 18 and times 3 would be -54
OpenStudy (agreene):
\(6x^2-54\) pull 6 out for each \(6(x^2-9)\) divide parenthetical statement \(6(x-3)(x+3\)
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OpenStudy (agreene):
right
OpenStudy (agreene):
now try the denominator
OpenStudy (dannyrod2000):
5(x+5)(x+3)?
OpenStudy (agreene):
taking out 5x would be more effective
OpenStudy (agreene):
since 15x is divisible
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OpenStudy (dannyrod2000):
oh ok
OpenStudy (agreene):
\[5x^2+15x \rightarrow 5x(x-3)\]
OpenStudy (agreene):
so, then we would combine them:
\[\frac{6(x-3)(x+3)}{5x(x-3)}\]
OpenStudy (dannyrod2000):
o so you cross out (x-3) and (x-3) and 6(x+3)/5x is the answer!
OpenStudy (agreene):
that can be the answer, technically you can simplify it a bit more. But that should be fine.
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OpenStudy (dannyrod2000):
um i got it wrong :(
OpenStudy (dannyrod2000):
it was 6(x-3)/5x
OpenStudy (agreene):
yeah
OpenStudy (agreene):
i put the wrong sign on the 2nd factor. thats mah bad
OpenStudy (agreene):
5x^2+15 -> 5x(x+3)