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example of quadratic equation that has no (0) real number solutions??
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@YanaSidlinskiy
One question before I do it, are you well familiar with completing the square ?
x^2-4x+53=0 has no real roots
No? Then I can't explain how to do it.
Bradely, in your equation the number can be 5 or more :)
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I mean the c>4 in ax²+bx+c=0
I mean when a=1 and b=2 (not necessarily in other cases)
b=4 (not 2)
Make b = 0 and you can write them all day. Just make everything else positive. \(4x^{2} + 1 = 0\) \(3x^{2} + 2 = 0\) \(7x^{2} + 9 = 0\)
Yes that's a good way,but I don't like the way the questions with b=0 look :)
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