Question

What is the equation, in point-slope form, of the line that has a slope of 6 and passes through the point (–1, –8)?

Answer 1

y-y1 = m(x-x1)
y+8= 6(x+1)
y+8=6x+6
6x-y-2=0

sourece: http://www.mathskey.com/question2answer/

Answer 2

Start from point-slope form:
y-y1=m(x-x1)
y+8 = 6(x+1)
Simplify:
y+8 = 6x+6
Subtract 6x from both sides:
-6x + y + 8 = 6
Subtract 8 to both sides:
-6x + y = -2
Multiply both sides by -1 to get a positive coefficient on x:
6x - y = 2

Answer 3

thankyou both of you! I am awful at math.

Answer 4

Anytime.