How do I put something in standard form

Question

anonymous · Answer

The points are ( 2, -5)    and     ( -1, 0)

anonymous · Answer

isn't that slope intercept form?

aum · Answer

y = mx + b is the slope-intercept form.

The standard form is: Ax + By = C

anonymous · Answer

what do I plug in where? @aum

aum · Answer

First find the equation of the line in slope-intercept form: y = mx + b
Then rearrange it to mx - y = -b  to put it in standard form.

First find slope: m = (y2-y1)/(x2-x1).

anonymous · Answer

Its going to be 5/-3

aum · Answer

yes, m = -5/3
y = -5/3x + b that passes through  ( -1, 0)
put x = -1, y = 0 and find b.

anonymous · Answer

b is going to be -2

aum · Answer

y = -5/3x + b that passes through ( -1, 0) 
put x = -1, y = 0 and find b.
0 = -5/3(-1) + b
0 = +5/3 + b
b = -5/3

aum · Answer

y = -5/3x - 5/3
multiply by 3:
3y = -5x - 5
add 5x:
5x + 3y =-5

anonymous · Answer

wait what are you doing

aum · Answer

Putting it in standard form: Ax + By = C