Question

I need to leave the secx alone
Sec^2x-1=secx+1

I need to know who answer anothers comments sorry i am new so i don't nothing!!

Answer 1

No problem! We are all here to help. :)
What do you need to solve for in this question?

Answer 2

I think, what you mean by leave sec x alone is that we have to solve for it.

Now let

sec x = y

You are given:
sec^2 x - 1 = sec x + 1
y^2 - y - 2 = 0

Factorize.

y^2 - 2y + y - 2 = 0
y(y-2) + 1(y-2) = 0
(y+1) (y-2) = 0

So, basically: y = -1,2
Which implies that: y = sec x = -1,2.

Getting this? :)