Mathematics
10 Online
OpenStudy (anonymous):
Write an equation of the line that is parallel to the given line
y = x + 3 and the given point (5,0).
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OpenStudy (anonymous):
if you ask this questin on yahoo answers they might help you faster this is to hard for me :P
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
parallel lines have equal slopes
for the line of the form y=mx+c m is the slope
so the slope of y = x + 3 or y=1x+3 is..
OpenStudy (anonymous):
ok ths antonio
OpenStudy (anonymous):
no problem :))
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OpenStudy (anonymous):
the equation of the line with slope m and passingh through (x1,y1) is given by
y-y1= m(x-x1)
OpenStudy (anonymous):
can you proceed with the above information
OpenStudy (anonymous):
ok matricked thks a lot :)
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
:) thks 4 tha medal
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OpenStudy (anonymous):
alternatively eq of the line parallel to y=x+3 is y=x+k you may find k using the statemnet that the reqd line passes through (5,0)
OpenStudy (anonymous):
yw
OpenStudy (kaptain_mittens):
Sorry but I need help on a question I asked 40 minutes ago but no one has helped can either of you come check out my question and help me?
OpenStudy (anonymous):
@matricked is it y=1x+3
OpenStudy (anonymous):
is that tha answer
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OpenStudy (anonymous):
pls i need 2 know tha answer 4 my test pls *-*
OpenStudy (anonymous):
can some1 help pls
OpenStudy (anonymous):
@paki
OpenStudy (paki):
matrickid has already explained...
OpenStudy (anonymous):
but is tha answer y=1x+3
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OpenStudy (anonymous):
@paki
OpenStudy (anonymous):
is that rite paki
OpenStudy (paki):
use this.... "the equation of the line with slope m and passingh through (x1,y1) is given by y-y1= m(x-x1)"
OpenStudy (anonymous):
so tha answer is not rite
OpenStudy (anonymous):
is it y=mx
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OpenStudy (anonymous):
i am so xD
OpenStudy (anonymous):
@paki
OpenStudy (anonymous):
sigh
OpenStudy (anonymous):
im tired nd cranky
can som1 pls explain more
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OpenStudy (anonymous):
ok
thks baby :)
call me sometime
OpenStudy (paki):
hhahah sure :)
OpenStudy (anonymous):
;)
OpenStudy (anonymous):
luv u <3 *kiss