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Mathematics 17 Online
OpenStudy (anonymous):

prove that tanA + tan( 60+A ) + tan ( 120 + A ) = 3tan3A

OpenStudy (anonymous):

first simplify tan( 60+A ) + tan ( 120 + A )

OpenStudy (anonymous):

did, and got tanA - 3+ tan^2 A / 1 - 3tan^2A

OpenStudy (anonymous):

near to the correct answer ?

OpenStudy (aum):

If I choose A = 10 degrees, then tan(10) + tan(70) + tan(130) is not 3tan(10). Are you sure the problem is correct?

OpenStudy (anonymous):

yes sir, the problem is correct.

OpenStudy (aum):

If you are asked to solve for A, then it is a different problem. But the given problem is not true for all A's. I tried A = 10 degrees and the LHS and RHS are not the same.

OpenStudy (anonymous):

oh wait. i missed out on 3 there!

OpenStudy (anonymous):

its 3tan3A and not 3tanA

OpenStudy (aum):

Now the problem is correct.

OpenStudy (anonymous):

im sorry for making it wrong, so how do u get the solution now ?

OpenStudy (aum):

Expand the second and third term. Then add all three terms on the LHS and simplify and see what you get.

OpenStudy (anonymous):

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