Question

Can anyone help in this chemistry question
https://mega.co.nz/#!Fx4XQILT!b-CAE5mTJzQ3kepRAB2qsmTFh5Nwmb3hUMpAh1YNvAk
here's the link link to the question paper and the question i am stuck on is question 1cii

Answer 1

can't see it without downloading it.

Answer 2

1 (a) Explain what is meant by the term ionisation energy.
(b) The first seven ionisation energies of an element, A, in kJ mol–1, are
1012 1903 2912 4957 6274 21 269 25 398.
(i) State the group of the Periodic Table to which A is most likely to belong. Explain your
answer.
(ii) Complete the electronic confi guration of the element in Period 2 that is in the same group
as A.
1s2
(c) Another element, Z, in the same period of the Periodic Table as A, reacts with chlorine to
form a compound with empirical formula ZCl 2. The percentage composition by mass of ZCl 2
is Z, 31.13; Cl , 68.87.
(i) Define the term relative atomic mass.
(ii) Calculate the relative atomic mass, Ar, of Z.
Give your answer to three signifi cant fi gures

Answer 3

1cii)

Answer 4

You have the hypothetical compound, \(\sf ZCl_2\), it mass percent position is:

\(\sf Mass~\%~composition_Z = \dfrac{M_Z}{M_Z+2M_{Cl}}*100\%=31.13~\%\)

M=molar mass

Solve for the molar mass of Z, \(\sf M_Z\).

Answer 5

Mz*100/100=31.13/100(MZ+71)
MZ=0.3113MZ+22.1023
0.6887MZ=22.1023
MZ=32.0
Sulphur

Answer 6

but sulphur is not a period 2 element.

Answer 7

I dont think A is in period 2

Answer 8

yes you are right i did not read the question properly.

Answer 9

thank you :D

Answer 10

no problem!