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OpenStudy (crashonce):
the period of tangent/cotangent is 360 degrees or pi
OpenStudy (anonymous):
tan(pi/2-theta)-sec(pi/2+4x+3)
OpenStudy (crashonce):
@Mavi.Pundir this is for @dg2 's question please delete your comments
OpenStudy (crashonce):
@ganeshie8
OpenStudy (anonymous):
ohh i am wrong
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ganeshie8 (ganeshie8):
both `cot(3x)` and `cos(4x+3` are periodic functions
so simply take the LCM of their periods to get the overall period
OpenStudy (anonymous):
3x*(4x+3) lcm?
OpenStudy (crashonce):
the period of cos is 360 and the period of cot is 180 @ganeshie8 are you saying to take the LCM so it is 180 deg?
OpenStudy (anonymous):
yes pi is the answer i think
ganeshie8 (ganeshie8):
period of cos(x) is 360
period of cos(4x+3) is 360/4 = 90, right ?
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OpenStudy (crashonce):
i think thats right
ganeshie8 (ganeshie8):
similarly,
period of cot(x) is 180
so period of cot(3x) would be 180/3 = 60
OpenStudy (anonymous):
i cant able to follow
ganeshie8 (ganeshie8):
take the LCM of 60 and 90
OpenStudy (anonymous):
180
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OpenStudy (anonymous):
i think the period of cos is 360 and cot is 180.then
OpenStudy (anonymous):
lol.@Mavi.Pundir
OpenStudy (anonymous):
i think you are new comer.
ganeshie8 (ganeshie8):
@Mavi.Pundir please do not spam, this question is already confusing...
OpenStudy (crashonce):
@Mavi.Pundir this is for dg2's question delete your usless comments
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OpenStudy (anonymous):
CrashOnce first tell me hot to get medals
ganeshie8 (ganeshie8):
i gave you one :)
just click on "Best Response" button on the right side of any reply
OpenStudy (anonymous):
thank you but you will delete it
OpenStudy (crashonce):
back to @dg2 's question please
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
i will also help
OpenStudy (anonymous):
okay.help me to solve
ganeshie8 (ganeshie8):
let me ask you a question :
imagine you're running around a circular track :
|dw:1406981074253:dw|
ganeshie8 (ganeshie8):
suppose if u run at `x m/s` speed, you take `180 seconds` to complete one round,
here is the question :
how much time will u take if u run at `3x m/s` speed ?
OpenStudy (anonymous):
60seconds
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ganeshie8 (ganeshie8):
how did u get 60 seconds ?
OpenStudy (anonymous):
so 360/4
OpenStudy (anonymous):
180/3
OpenStudy (anonymous):
so 360/4 but there is addition of 3
OpenStudy (anonymous):
but addition of 3
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ganeshie8 (ganeshie8):
yes, we use the same logic :
cot(x) runs at x m/s and completes one cycle in 180 seconds
cot(3x) runs at 3x m/s and completes one cycle in 180/3 seconds
ganeshie8 (ganeshie8):
can you figure out the period of cos(4x+3) using the same logic ?
OpenStudy (anonymous):
yes 360/4+3
ganeshie8 (ganeshie8):
forget about the addition of 3, its just a phase difference... (the starting point of ur run) it won't affect the period
OpenStudy (anonymous):
90
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ganeshie8 (ganeshie8):
cos(x) runs at x m/s and completes one cycle in 360 seconds
cos(4x+3) runs at 4x m/s and completes one cycle in 360/4 seconds
ganeshie8 (ganeshie8):
so we have below :
period of cot(3x) = 60
period of cos(4x+3) = 90
OpenStudy (anonymous):
we get 180
ganeshie8 (ganeshie8):
Yep !
OpenStudy (anonymous):
i got it @ganeshie8
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