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Mathematics 16 Online
OpenStudy (anonymous):

period of cot 3x-cos(4x+3) is

OpenStudy (crashonce):

the period of tangent/cotangent is 360 degrees or pi

OpenStudy (anonymous):

tan(pi/2-theta)-sec(pi/2+4x+3)

OpenStudy (crashonce):

@Mavi.Pundir this is for @dg2 's question please delete your comments

OpenStudy (crashonce):

@ganeshie8

OpenStudy (anonymous):

ohh i am wrong

ganeshie8 (ganeshie8):

both `cot(3x)` and `cos(4x+3` are periodic functions so simply take the LCM of their periods to get the overall period

OpenStudy (anonymous):

3x*(4x+3) lcm?

OpenStudy (crashonce):

the period of cos is 360 and the period of cot is 180 @ganeshie8 are you saying to take the LCM so it is 180 deg?

OpenStudy (anonymous):

yes pi is the answer i think

ganeshie8 (ganeshie8):

period of cos(x) is 360 period of cos(4x+3) is 360/4 = 90, right ?

OpenStudy (crashonce):

i think thats right

ganeshie8 (ganeshie8):

similarly, period of cot(x) is 180 so period of cot(3x) would be 180/3 = 60

OpenStudy (anonymous):

i cant able to follow

ganeshie8 (ganeshie8):

take the LCM of 60 and 90

OpenStudy (anonymous):

180

OpenStudy (anonymous):

i think the period of cos is 360 and cot is 180.then

OpenStudy (anonymous):

lol.@Mavi.Pundir

OpenStudy (anonymous):

i think you are new comer.

ganeshie8 (ganeshie8):

@Mavi.Pundir please do not spam, this question is already confusing...

OpenStudy (crashonce):

@Mavi.Pundir this is for dg2's question delete your usless comments

OpenStudy (anonymous):

CrashOnce first tell me hot to get medals

ganeshie8 (ganeshie8):

i gave you one :) just click on "Best Response" button on the right side of any reply

OpenStudy (anonymous):

thank you but you will delete it

OpenStudy (crashonce):

back to @dg2 's question please

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i will also help

OpenStudy (anonymous):

okay.help me to solve

ganeshie8 (ganeshie8):

let me ask you a question : imagine you're running around a circular track : |dw:1406981074253:dw|

ganeshie8 (ganeshie8):

suppose if u run at `x m/s` speed, you take `180 seconds` to complete one round, here is the question : how much time will u take if u run at `3x m/s` speed ?

OpenStudy (anonymous):

60seconds

ganeshie8 (ganeshie8):

how did u get 60 seconds ?

OpenStudy (anonymous):

so 360/4

OpenStudy (anonymous):

180/3

OpenStudy (anonymous):

so 360/4 but there is addition of 3

OpenStudy (anonymous):

but addition of 3

ganeshie8 (ganeshie8):

yes, we use the same logic : cot(x) runs at x m/s and completes one cycle in 180 seconds cot(3x) runs at 3x m/s and completes one cycle in 180/3 seconds

ganeshie8 (ganeshie8):

can you figure out the period of cos(4x+3) using the same logic ?

OpenStudy (anonymous):

yes 360/4+3

ganeshie8 (ganeshie8):

forget about the addition of 3, its just a phase difference... (the starting point of ur run) it won't affect the period

OpenStudy (anonymous):

90

ganeshie8 (ganeshie8):

cos(x) runs at x m/s and completes one cycle in 360 seconds cos(4x+3) runs at 4x m/s and completes one cycle in 360/4 seconds

ganeshie8 (ganeshie8):

so we have below : period of cot(3x) = 60 period of cos(4x+3) = 90

OpenStudy (anonymous):

we get 180

ganeshie8 (ganeshie8):

Yep !

OpenStudy (anonymous):

i got it @ganeshie8

ganeshie8 (ganeshie8):

good :)

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