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PLEASE HELP!!!!!!!!!!!! Write x^2 - 2x - 3 = 0 in the form (x - a)^2 = b, where a and b are integers. (x - 4)^2 = 3 (x - 3)^2 = 2 (x - 2)^2 = 1 (x - 1)^2 = 4
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@thomaster @dan815 @abb0t
@dan815
@ganeshie8 @zzr0ck3r
@RosieF @abb0t @dan815
y did u tag me on my own question @zzr0ck3r ?
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it seems like that was the thing to do
\(x^2+bx+c=0 \implies (x+\frac{b}{2})^2=-c+(\frac{b}{2})^2\)
\(b=-2, c=-3\)
so b/2 = -1 and there is only one option
so it's d?
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correct
thanks :)
fo she z
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