easy/medium geometry question. I've gotten really rusty at this. so far, I've found angle 4= 90 angle 8 = 90 maybe angle 1 = 63.5 angle 4 maybe = 116.5 These are the answer choices to match with. 29.5° 121° 124 ° 54° 116.5° 63.5° 90°
** angle 6= 116.5 is there a way to explain how we get these answers? : o aside from using compass, etc.
are we given that BD = diameter and DH = tangent ?
I think it is tangent.
whats the given info ?
but I'm not positive that angle 4 is 90. Match angles 1-7 with the following degrees
angle 4 is 90 if DH is tangent cuz \(\large \text{radius} \perp \text{tangent}\)
ok that's true, then angle 4 is 90. How do I continue?
you're correct about angle 8 too, it has to be 90 as it is a semicircle angle
Oh that's lucky : D , what about 1 and 6? Since they add up to be a straight line, I just try to find 2 answer choices that sums to 180... not sure if it's right though. The rest, I'm stuck.
angle6 = 116.5° angle1 = 63.5° (why ?)
we're on same page on that :)
only those two angles addup to 180 in the given options, so we can conclude on angles 1 and 6
now we have to find other angles with what we know so far. I searched up a list of circle properties, not sure if we can apply anything here.
angle 1 = angle 3 + (angle 2 - angle 4)
therefore angle 3 + angle 2 = 153.5
that gives relation between angles 2 and 3 lets try and get another relation between them so that we can solve the system of equations
great! Now it looks a little bit more solvable :))
lets look at angle 5 : |dw:1407010224391:dw|
|dw:1407010363045:dw|
those two angles will be same
ohh I see that now : o
for some reason I thought angle 5 = 45, but that's not true right?
one more relation : angle 3 = (180 - angle 7)/2
ohhh because it's the triangle is made up of two radius and a line , isosceles triangle
inscribed angle = (central angle) / 2
I see : o I forgot that formula.
|dw:1407010955420:dw|
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