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Mathematics 19 Online
OpenStudy (yanasidlinskiy):

Can you believe?

OpenStudy (yanasidlinskiy):

Doing my bros college work:D @ganeshie8

OpenStudy (yanasidlinskiy):

@ash2326

OpenStudy (ash2326):

@YanaSidlinskiy do you need help solving the problem?

OpenStudy (rational):

this is your bro's homework ? you're helping him is it

OpenStudy (yanasidlinskiy):

No. I was just showing you what I'm doing right now:D I figured it out though like after 30 minutes:D

OpenStudy (ash2326):

oh cool :D

OpenStudy (ash2326):

Shouldn't he do the homework? ;)

OpenStudy (yanasidlinskiy):

Yea. He's just being lazy. Everytime he doesn't wanna do work, he's like...yana, go do it:D Yea. But....I'm that niceXD:D

OpenStudy (yanasidlinskiy):

Pretty much like cheating:). But...that shows how nice I am:D

OpenStudy (rational):

factoring by grouping is fun... we cannot do it always though ! most polynomials are not that nice... however the ones we deal with in homework are cooked up to be factorable and so they are always nice !!

OpenStudy (yanasidlinskiy):

Yep! I agree.

OpenStudy (rational):

try to factor `x^3 + x + 1` in your free time :)

OpenStudy (yanasidlinskiy):

Umm..Not those kind though. I've never been taught how to factor. But I just go by the examples. Lemme see if I can get this one though.

OpenStudy (rational):

just a headsup - its very hard to factor... regular methods wont work : http://www.wolframalpha.com/input/?i=factor+x^3+%2B+x+%2B+1&dataset=

OpenStudy (yanasidlinskiy):

XD. I knew something was wrong. Couldn't do anything. Idk.

OpenStudy (rational):

it is supposed to be very hard haha! its just a bad example to remind us that not everything is factorable by grouping and there are other cool methods waiting in higher math :)

OpenStudy (yanasidlinskiy):

Lol. I haven't gotten there yetXD. That's not for meh. Lol.

OpenStudy (yanasidlinskiy):

Now I really do have a question:)

OpenStudy (yanasidlinskiy):

Sorry. That was the wrong oneXD \[2x ^{2}-10xy-7x+35y\]

OpenStudy (yanasidlinskiy):

How would I factor \(\huge{\uparrow}\) out?

OpenStudy (rational):

group first two terms, group last two terms

OpenStudy (rational):

\[\large 2x^2-10xy-7x+35y\] \[\large (2x^2-10xy) + (-7x+35y)\]

OpenStudy (rational):

factor out the GCF from first group

OpenStudy (rational):

whats the GCF of first group ? (first two terms)

OpenStudy (yanasidlinskiy):

Not sure. I worked it out several times. But I have a final answer as: (x-5y)(2x-7)

OpenStudy (rational):

thhats right! but you need to know GCF to work this problem step by step

OpenStudy (yanasidlinskiy):

Ok. Want me to show my steps?

OpenStudy (rational):

yes

OpenStudy (yanasidlinskiy):

2x^2-10xy=2x(x-5y) -7x+35=-7(x-5y)=2x^2-10xy-7x+35y=2x(x-5y)-7(x-5y) 2x(x-5y)-7(x-5y)=(x-5y)(2x-7) Sorry if it doesn't make sense.

OpenStudy (rational):

it makes very good sense :) good job ! you're factoring out GCF without knowing that you're doing it...

OpenStudy (rational):

your first line : 2x^2-10xy= `2x`(x-5y) `2x` is the GCF of first group

OpenStudy (yanasidlinskiy):

Hahaha!!:D Ok. I *think* i got the hang of it<3

OpenStudy (rational):

I can see you're very good in math ;) also you should teach ur bro and let him do his work ! don't *spoil* his discovery of concepts by doing all his work (just saying...)

OpenStudy (yanasidlinskiy):

Hahhaha!!:D I'm not that good in math to tell you the truth. I still have a long way to go. Lol. I won't spoil it. XD.

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