Question

The sum of three consecutive integers is 267. What is the largest integer?

Answer 1

Let n = the largest number
Let n-1= second larrgest, consecutive
Let n -2 = smallest of those consecutive #s

n + (n-1) + n(-2) = 267
n+ n + n -3 = 267
3n = 270
n= ?
Can you find it now?

Answer 2

Maybe I'm not sure yet but thanks!

Answer 3

+ (n-2) **

Answer 4

Is there anything confusing? Lemme know.

Answer 5

n= 90.

so now you can check if you're unsure.
biggest #= 90
next biggest = 89
smallest = 88

90 + 88 + 89 = 267
checked

Answer 6

Thanks so much do you mind explaining the steps? I have a test on this in a week.

Answer 7

Ok , you want find a number right?
Let that number be a n.

Is this clear?

Answer 8

"Now it says the sum of three consectutive numbers."
sum means adding them. consecutive means that the number are next to each other.

Answer 9

so, let n be your biggest number.

Answer 10

got it so far

Answer 11

the number that's consecutive (next to) and smaller than n is
n-1.

LIke the consecutive, smaller number of 10 is 9 (for example.)

so we have

n and n-1 so far.

Answer 12

okay i think im getting it thanks!

Answer 13

and the number that's consecutive and smaller than n-1, is n-2.

so we have n , n-1, and n-2

now to find the sum , we add these 3 together.

Answer 14

n + n-1 + n-2 = 267

and from there you solve the problem.

Answer 15

@rational are you on stalking mode? xDD (I just noticed)

Answer 16

lol just entered this thread as the problem seems interesting, want me leave ha :o

Answer 17

oh sorry I didn't mean it that way! xDD Come back to me, rational!

Answer 18

jk haha! it seems sum of 3 consecutive integers is always odd hmm

Answer 19

another (similar) way @AndreaEwen
(n-1) + (n) + (n+1) = 267
3n = 267
n = 89

so the required numbers are : 88,89,90
you can pick the largest number^^

Answer 20

thank you! @rational

Answer 21

good thinking! :)