A photo is 6 inches long. Kamala enlarged the photo so that it is twelve inches long. By keeping the same proportion of the photo, what would be the width of the photo if the enlarged photo is 8 inches wide? Two images of rectangles. The first is six inches long and ? wide. The second is twelve inches long and eight inches wide Does this relationship represent direct or inverse variation? (1 point) Using the appropriate formula, find k. (1 point) Show your work and calculate the width of the original photo. (2 points)
help please
\[\frac{ 6 }{ 12 }=\frac{ x }{ 8 }\] Solve for x.
4
good, thats teh first one.
you had to set up the ratio like that.
ok so it is 4 wide
ok so what you see here is when the height increases, it is directly proportional, since both height and width are modeled by a direct ratio.
oh that makes sense
hm...idk what the stuff about "k" is and original formula. My best guess is they want the exact direct proportion, so you'd have something like h=k*w where h is height and w is width
ok thank you
or maybe they are looking for constant of proportionality, so k in this case is 2.
sorry, I can't remember the generic formula
is alright thank you so much for your help
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