Sodium sulfate reacts with carbon to produce the products sodium sulfide and carbon monoxide. Identify the reducing agent in the following reaction. Na2SO4 + 4C Na2S + 4CO C Na2SO4 CO Na2S
@Abhisar ?
HIII
What is reducing agent ?
Hello !
a reducing agent loses electrons
and it is oxidized
yes that's correct ! Now which one do u think is oxidized after the reaction ?
okay that is my problem :'( I am stuck between Na2SO4 and Na2S because those are the ones involved in the reduction
Do u know how to write oxidation numbers ?
uh well sort of... but I will go with no
Do u hav to learn it in ur course ?
nah it is a pre test that does even count but i wanna learn now :)
♦ The oxidation state of an uncombined element is zero. ... ♦ The sum of the oxidation states of all the atoms or ions in a neutral compound is zero. ♦ The sum of the oxidation states of all the atoms in an ion is equal to the charge on the ion.
oh so do i have to find that for each element ?
yes, find for each one and see which one is reduced
I'll workout an example for you
Let's calculate for C in the reactant side and product side
kk but i was working the problem out I think i got it but i wanna hear your ex first :p
um okay so how do i do that ?
in reactant hand side carbon is C, so its oxidation number by rule 1 will be 0. Got it ?
yes
In the product hand side it's in the form of CO. Now oxidation state of O is always (almost, except in the case of OF) equal to -2. So if that of C is xthen, X-2=0 [because CO is neutral,Rule 2] x=+2
So we can see that carbon was 0 before reaction and became +2 after reaction. This means it is oxidized
Getting it ?
yes i think so
I know u didn't get it ;p
:) just i little bit
btw reducing agent is carbon. All u need to know is how to calculate oxidation state.
u have the link to my web page ?
no
Go to this one and you will find a link to @Somy 's oxidation state tutorial.
yup i got it, i'll take a good look at it! Thank you for your time and help! :D
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can i let you know what i think the answer is after l learned ?
sure :)
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