Question

value of K to make a perfect square: p+1/4root(p)+k^2?

Answer 1

hey aryan :)
\(for ~ ~ x^2+bx\)
the constant that can be added to make the expression, a perfect square is
\((b/2)^2 \)

so for
\(p +(1/4)\sqrt p \)
we add,
\(\Large k^2 = (1/2 \times 1/4)^2\)

find k from here :)

Answer 2

basically just half of the co-efficient of middle term :)

Answer 3

yeah got it. Answer is +/-(1/8).

Answer 4

thats \(\huge \checkmark \) :)

Answer 5

Thanks for helping :)

Answer 6

welcome ^_^