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OpenStudy (anonymous):
Solve 3x^2 - 4x - 6 = 0 by factoring.
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OpenStudy (anonymous):
is the equation not, 3x^2-3x-6 ?
OpenStudy (anonymous):
3x^2 - 4x - 6 = 0
OpenStudy (anonymous):
the best way to do this is quadratic formula.
OpenStudy (anonymous):
I just get the numbers wrong... when I do it..
OpenStudy (anonymous):
is the sum from a textbook?
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OpenStudy (dan815):
unfoil it
OpenStudy (dan815):
@Kainui
OpenStudy (anonymous):
I got x=4 x=6
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
I tried to quad formula...
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OpenStudy (anonymous):
well the simplest way is the quad formula.
OpenStudy (anonymous):
\[\large ax^{2} + bx + c = 0\]
\[\large 3x^{2} -4x -6 = 0\]
a= 3 b = -4 c = -6
OpenStudy (anonymous):
The quadratic formula is
\[\large \frac{ -b \pm \sqrt{b^{2} -4ac} }{ 2a }\]
\[\large \frac{4 \pm \sqrt{4^{2} -4(3)(-6)} }{ 2(3) }\]
\[\large = \frac{4 \pm \sqrt{16 +72} }{ 2(3) }\]
\[\large = \frac{4 \pm \sqrt{88} }{ 2(3) }\]
OpenStudy (anonymous):
(3x-2)(x+3)
OpenStudy (anonymous):
\[\large = \frac{4 \pm 2\sqrt{22} }{ 2(3) }\]
\[\large = \frac{2 \pm \sqrt{22} }{ (3) }\]
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OpenStudy (anonymous):
set that equal to 0 and you get x=2/3 and x = -3
OpenStudy (anonymous):
(3x-2) (x+3)
= 3x^2 -2x +9x -6
\[= 3x^{2} -7x +6\]
We need -4x
OpenStudy (anonymous):
=3x^2 + 7x -6 ***
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