Solve 3x^2 - 4x - 6 = 0 by factoring.
is the equation not, 3x^2-3x-6 ?
3x^2 - 4x - 6 = 0
the best way to do this is quadratic formula.
I just get the numbers wrong... when I do it..
is the sum from a textbook?
unfoil it
@Kainui
I got x=4 x=6
how?
I tried to quad formula...
well the simplest way is the quad formula.
\[\large ax^{2} + bx + c = 0\] \[\large 3x^{2} -4x -6 = 0\] a= 3 b = -4 c = -6
The quadratic formula is \[\large \frac{ -b \pm \sqrt{b^{2} -4ac} }{ 2a }\] \[\large \frac{4 \pm \sqrt{4^{2} -4(3)(-6)} }{ 2(3) }\] \[\large = \frac{4 \pm \sqrt{16 +72} }{ 2(3) }\] \[\large = \frac{4 \pm \sqrt{88} }{ 2(3) }\]
(3x-2)(x+3)
\[\large = \frac{4 \pm 2\sqrt{22} }{ 2(3) }\] \[\large = \frac{2 \pm \sqrt{22} }{ (3) }\]
set that equal to 0 and you get x=2/3 and x = -3
(3x-2) (x+3) = 3x^2 -2x +9x -6 \[= 3x^{2} -7x +6\] We need -4x
=3x^2 + 7x -6 ***
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