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Mathematics 9 Online
OpenStudy (anonymous):

Hey guys, Im stuck on this problem. Given f'(tanx)=tanx what is f'(x) = any advice will help thanks and i will give medals :)

OpenStudy (anonymous):

okay i got it its x/(1+x^2)

OpenStudy (anonymous):

f'(tanx) = tanx/sec^2(x) f'(x)= x/(1+x^2)

OpenStudy (anonymous):

\(f'\color{red}{(tanx)}=\color{red}{tanx}\) \(f'\color{red}{(you)}=\color{red}{you}\) \(f'\color{red}{(me)}=\color{red}{me}\) how about \(f'\color{red}{(x)}=\color{red}??\)

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