8a-1/6a+8=3/4 having problems finding the variable.
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OpenStudy (ray_sihota):
would my Lcd be 6a+8(4)
OpenStudy (anonymous):
\(\Large 8a-\frac{1}{6a}+8=\frac{3}{4}\\\Large a(8a-\frac{1}{6a}+8)=\frac{3}{4}a\\\Large 8a^2-\frac{1}{6}+8a-\frac{3a}{4}=0\\\Large 8a^2+\frac{29a}{4}-\frac{1}{6}=0\)
Now, use Quadratic Formula we got:
\(\huge \color{blue}{a=\frac{\frac{-29}{4}\pm\sqrt{(\frac{29}{4})^2+4\times8\times \frac{1}{6}}}{2\times8}}\)
OpenStudy (nikato):
or is your problem like this?
\[\frac{ 8a-1 }{ 6a+8 }=\frac{ 3 }{ 4 }\]
OpenStudy (ray_sihota):
yes
OpenStudy (ray_sihota):
i got the lcd 6a+8(4)
4(8a-1)=3(6a=8)
32a-4=18a+24
14a=28
a=2
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OpenStudy (nikato):
yup. thats is correct
OpenStudy (nikato):
although i dont know why u call it lcd. isnt it just cross multiply?
OpenStudy (ray_sihota):
that how we do it in class . Multiply the LCD with all the equations and cross out the common factor less chance of mistakes.
OpenStudy (nikato):
ok then... but anyways, your answer is correct
OpenStudy (ray_sihota):
thanks again
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