8a-1/6a+8=3/4 having problems finding the variable.

Question

ray_sihota · Answer

would my Lcd be 6a+8(4)

anonymous · Answer

$\Large 8a-\frac{1}{6a}+8=\frac{3}{4}\\Large a(8a-\frac{1}{6a}+8)=\frac{3}{4}a\\Large 8a^2-\frac{1}{6}+8a-\frac{3a}{4}=0\\Large 8a^2+\frac{29a}{4}-\frac{1}{6}=0$ 

Now, use Quadratic Formula we got:

$\huge \color{blue}{a=\frac{\frac{-29}{4}\pm\sqrt{(\frac{29}{4})^2+4\times8\times \frac{1}{6}}}{2\times8}}$

nikato · Answer

or is your problem like this?

$$\frac{ 8a-1 }{ 6a+8 }=\frac{ 3 }{ 4 }$$

ray_sihota · Answer

yes

ray_sihota · Answer

i got the lcd 6a+8(4)
4(8a-1)=3(6a=8)
32a-4=18a+24
14a=28
a=2

nikato · Answer

yup. thats is correct

nikato · Answer

although i dont know why u call it lcd.  isnt it just cross multiply?

ray_sihota · Answer

that how we do it in class . Multiply the LCD with all the equations and cross out the common factor less chance of mistakes.

nikato · Answer

ok then... but anyways, your answer is correct

ray_sihota · Answer

thanks  again

nikato · Answer

no problem