If tan theta= 15/8, then: A. sec theta = 17/8 B. cos theta = 15/17 C. cot theta = 8/15 D. csc theta = 17/15 There's potentially more than one answer.
Well we know \[\large tan = \frac{sin}{cos} = \frac{15}{8}\] This tells us that sin = 15 and cos = 8
So a good hint, cos is not represented as a fraction..so B does not make sense
Now, Lets begin with A \[\large sec \theta = \frac{1}{cos} = \frac{1}{8}\] Secant can be written as 1/cos...and since we know cos = 8 we would have 1/8 So A is out as well
Now D \[\large csc\theta = \frac{1}{sin} = \frac{1}{15}\] cosecant can be written as 1/sin and since we know sin = 15... So D is out
And finally C \[\large \cot\theta = \frac{1}{tan} = \frac{1}{\frac{sin}{cos}} = \frac{cos}{sin} = \frac{8}{15}\] Here we have our answer!
Is the key just memorizing when to use sin/cos/tan and SOACAHTOA or whatever?
it is incorrect to say sin theta is 15 and cos of theta is 8. the outputs should be between -1 and 1
build a right triangle base on what is given then find the hyp
then you can find sin of theta cos of theta and so on based off that triangle
Refer to the one line calculation using Mathematica v9.
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