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OpenStudy (anonymous):
is \[ \sum_{n=0}^{\infty} 5^{n+2} 3^{-2n}\]
a geometric series? if, so find its initial term a, common ration r and the sum
OpenStudy (anonymous):
ratio*
OpenStudy (anonymous):
put n=0 to get the first term
OpenStudy (anonymous):
here first term is 25
OpenStudy (anonymous):
second term is 125/9
so common ratio is (125/9 ) /25 =5/9
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OpenStudy (anonymous):
how did u get the second term?
OpenStudy (anonymous):
@matricked
OpenStudy (anonymous):
so thats it for finding the initial term a, common ration r and the sum s?
OpenStudy (anonymous):
*ratio
OpenStudy (anonymous):
for second term n=1
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OpenStudy (anonymous):
here r=5/9 < 1
so sum to infinity = first term / (1 - r )
OpenStudy (anonymous):
sum= 25/(1-5/9) =225/4
OpenStudy (anonymous):
thank you! great help
can you help with this find the sum of the telescoping series using Partial fraction decomposition
\[\sum_{n=1}^{\infty} \frac{ 1 }{ n ^{2} +3^{n} }\]
OpenStudy (anonymous):
do i break the denominator into n(n+3) ?
OpenStudy (anonymous):
@matricked
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