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integral of dx over (a-x) to power 3
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assume a-x =z then -dx= dz or dx=-dz
\[ \large \int {dx \over {(a-x)^3}} = \int (a-x)^{-3}dx\] This looks like a good place for advanced guessing. Since the exponent is -3 we know the antiderivate must involve the power -2, So what does the derivative of \( (a-x)^{-2} \) look like?
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