Mathematics
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OpenStudy (eric_d):
Simplify
(cos5theta-cos theta)/ (sin5theta-sin theta)
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OpenStudy (eric_d):
@nirmalnema
OpenStudy (eric_d):
= cos5 cos - sin5 sin
is this correct so far ?
OpenStudy (eric_d):
@UnkleRhaukus
OpenStudy (eric_d):
@ganeshie8
OpenStudy (eric_d):
@paki
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OpenStudy (nirmalnema):
OpenStudy (paki):
= cos5 cos - sin5 sin ==== > how you obtained this
OpenStudy (eric_d):
yes @paki
OpenStudy (nirmalnema):
@eric_d can you simplify it further
OpenStudy (anonymous):
see this formula.you will get direct answer
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OpenStudy (anonymous):
cos(a-b) = cosa cosb + sina sinb
OpenStudy (anonymous):
cos(5θ) cos(θ) + sin(5θ) sin(θ)
= cos(5θ - θ)
= cos(4θ)
OpenStudy (eric_d):
the given answer is -tan 3 theta
OpenStudy (nirmalnema):
@dg2 there is division not addition
OpenStudy (anonymous):
cos(5θ - θ)/sin(5θ - θ) is this the question
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OpenStudy (eric_d):
(cos5theta-cos theta)/ (sin5theta-sin theta)
OpenStudy (anonymous):
same ya so we get cos 4θ/sin4θ
OpenStudy (nirmalnema):
how do u get that
OpenStudy (anonymous):
take cos as common in numerator and sin as common in denominator?
OpenStudy (nirmalnema):
that a rubbish thing u cant do that
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OpenStudy (paki):
@nirmalnema be cool.. .try to lecture them regarding this please... :)
OpenStudy (anonymous):
if i made a blunder i am sorry @nirmalnema
OpenStudy (eric_d):
It's alrite........
Thanks everybody...
@MM is guiding me..
OpenStudy (nirmalnema):
@dg2 its ok no problem.!!
but always remember this its wrong you cant take it out common like that
OpenStudy (anonymous):
multiply cos 3θ in numertor and denominator first