Question

Find a cubic function whose graph has horizontal tangents at the points (-2,6) and (2,0)

Answer 1

I thought I knew how to do this. The horizontal tangents mean that those are the extrema, and therefore the slope at those points is 0, and are therefore the roots of f'(x), so I tried that and multiplied (x-2)(x+2) to get the derivative, then integrated to get the function, but something (or all of that) is off because I was far off from the answer

Answer 2

@Kainui