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@iambatman
i mean A ,D ,E
D and E are correct. Why did you also include A?
x^2=0 x=0
Yeah :)
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0 isn't a vertical asymptote
D and E are
O: it was D,E
You need to really should check again before answering the question.
:(
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Twice now :P
The denominator contains (x + 2)(x - 7) If you set that equal to zero, you get only two solutions: x = -2 or x = 7 The asymptotes are only at x = -2 and x = 7. There is no solution x = 0, so there is no asymptote at x = 0.
thanks :p
You're welcome.
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