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Mathematics 13 Online
OpenStudy (dannyrod2000):

http://prntscr.com/49jlh5

OpenStudy (dannyrod2000):

@iambatman

OpenStudy (dannyrod2000):

i mean A ,D ,E

OpenStudy (mathstudent55):

D and E are correct. Why did you also include A?

OpenStudy (dannyrod2000):

x^2=0 x=0

OpenStudy (anonymous):

Yeah :)

OpenStudy (anonymous):

0 isn't a vertical asymptote

OpenStudy (anonymous):

D and E are

OpenStudy (dannyrod2000):

O: it was D,E

OpenStudy (anonymous):

You need to really should check again before answering the question.

OpenStudy (dannyrod2000):

:(

OpenStudy (anonymous):

Twice now :P

OpenStudy (mathstudent55):

The denominator contains (x + 2)(x - 7) If you set that equal to zero, you get only two solutions: x = -2 or x = 7 The asymptotes are only at x = -2 and x = 7. There is no solution x = 0, so there is no asymptote at x = 0.

OpenStudy (dannyrod2000):

thanks :p

OpenStudy (mathstudent55):

You're welcome.

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