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Evaluate the expression r^3+4r^2s for r=-2 and s=3. The solution is .
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\(\normalsize\color{blue}{ r^3+4r^2s }\) \(\normalsize\color{blue}{ (-2)^3+4(-2)^2(3) }\)
simply plug in the variables
\(\normalsize\color{blue}{ -8+4(4)(3) }\) \(\normalsize\color{blue}{ =? }\)
-4+12?
Mhm?
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What is \[4 \times 4 \times 3? \]
48?
Yes, now what's 48-8?
40
:)
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thats not it..ughh
Yes it is, it is 40 :)
i tried it
That's because you gave us the wrong value for r....it's -3 not -2 haha.
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and s =2, you had it backwards
haha omgi swear i copied and pasted.. hmm they must've switched it to trick me
\[r^3+4r^2s \implies (-3)^3+4(-3)^2(2)\]
-27 + 4(9) (2)?
Yeah
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-27+72?
45
It's arithmetic you shouldn't have to ask me :P, but yes that's right.
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