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Eliminate the parameter. x = t + 4, y = t^2
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solve x=t+4 for t then replace the t in y=t^2 and then done
@notmathnerd do you understand?
yes I do thank you
would it be y=x^2 - 16 ? @myininaya
hmmm not correct but i think it is because you forgot a simple algebraic rule (and don't worry a lot of people forget it)
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(a-b)^2 doesn't meant a^2-b^2
(a-b)^2 means (a-b)(a-b)
so what am i saying is i'm pretty sure you got this far y=(x-4)^2 but you didn't expand the (x-4)^2 correctly that is all
So the answer is actually x^2 - 8x + 16?
the answer is actually y=x^2-8x+16
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ok thank you
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