Indefinite Integrals using Basic Rules of Integration
\[\int\limits \frac{ x ^{4} +2x ^{2} +1 }{ x ^{2} }\]
*dx
Glad you remembered that 'dx.' Hint: break this integral into three separate integrals. In the first two cases, reduce the fraction. In the third case, use a negative exponent to represent 1/ (x^2).
\[\int\limits x^4 + \int\limits 2x ^{2} + \int\limits 1\]you mean like
and I integrate each one? @mathmale
Givanna: what happened to your denominator, x^2? Also, what happened to "dx?" Yes, integrate each integral separately and then add the results together with just one constant of integration, C.
So your first (of three) integrals will be Int [(x^2)dx ].
\[\int\limits \frac{ x^4 }{ x^2 } dx + \int\limits \frac{ 2x ^{2} }{ x^2 } dx + \int\limits \frac{ 1 }{ x^2 } dx\]
\[\int\limits x^2 dx + \int\limits 2 dx + \int\limits x^-2 dx\]
\[\frac{ x^3 }{ 3 } + 2x - \frac{ 1 }{ x } +c\]
@mathmale
Surely looks good! If you want to check your answer, differentiate all four terms. Combine the results using the LCD.
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