Question

How to find the integral of 4x/(x^2-1)^2 dx

This is what I did but I'm not sure about it

Answer 1

4 integral x(x^2-1)^-2 dx

Answer 2

U=x^2-1
Du=2x dx

Answer 3

just let u = x^2 -1, you have du =2x dx, that's enough

Answer 4

Ok

Answer 5

And what do I do next?

Answer 6

du = 2x dx --> xdx =1/2 du, ok?

Answer 7

So it's 4 times 1/2 from the outside

Answer 8

you can simplify it , right?